If 200 MeV energy is released in the fission of a single nucleus of ""_(92)^(235)U how many fissions must occur per second to produce a power of 1k W

If 200 MeV energy is released in the fission of a single nucleus of ""

1.	If 200 MeV energy is released in the fission of a single nucleus of ""_(92)^(235)U how many fissions must occur per second to produce a power of 1k W
Answer» `22222 "sec"^(-1)` `3.2 xx 10^(-11) "sec"^(-1)` `31.25 xx 10^(13) "sec"^(-1)` `31.25 xx 10^(12) "sec"^(-1)` SOLUTION :Energy released PER fission = 200 MeV `=200xx10^(6) eV=200xx10^(6)xx1.6xx10^(-19) J` `=3.2xx10^(-11) J` But ENREGY needed =1 kW `1xx10^(3) W=1xx10^(3) J s^(-1)` Number of fissions required `=("Energy required")/("Energyreleased per fission")` `=(1xx10^(3) J s^(-1))/(3.2xx10^(-11))=3.125 xx10^(13) s^(-1)`