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If 200 MeV energy is released per fission of `._(92)U^(235)` How many fissions must occur per second to produce a power of 1m W?A. `3.5xx10^(10)`B. `4.2xx10^(11)`C. `3.125xx10^(12)`D. `3.125xx10^(13)` |
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Answer» Correct Answer - D `n(200"Mev")=1"kW"` `impliesn=(1000)/(200xx10^(6)xx1.6xx10^(-19))=3.125xx10^(13)` |
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