1.

If 216g residue is obtained from 0.5 ml silver salt,

Answer»

`N = 4`
`n = 2`
MOLAR MASS of salt `=718g//MOL`
Molar of mass of sat `=388g mol`

Solution :`0.5 xx n = (216)/(108)`mol of `Ag n = 4`
molar mass `=58 +(165) n = 718g//mol`


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