If 23x = x, then log 59 in terms of x is (1) \(\frac{x+1}{x-1}\)(2) \(\frac{2}{x-1}\)(3) \(\frac{x}{x+1}\)(4) \(\frac{x-1}{x}\)

If 23x = x, then log 59 in terms of x is (1) \(\frac{x+1}{x-1}\)(2

1.	If 23x = x, then log 59 in terms of x is (1) \(\frac{x+1}{x-1}\)(2) \(\frac{2}{x-1}\)(3) \(\frac{x}{x+1}\)(4) \(\frac{x-1}{x}\)
Answer» Correct option is (2) \(\frac{2}{x-1}\)

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If 23x = x, then log 59 in terms of x is (1) \(\frac{x+1}{x-1}\)(2) \(\frac{2}{x-1}\)(3) \(\frac{x}{x+1}\)(4) \(\frac{x-1}{x}\)

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