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If 25 ml 0.2 M Ca(OH)_2 is neutralized by 10 ml, 1 M HCl than the pH of solution is ….. |
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Answer» 1.37 `=2xxM_1xxV_1` `=2xx0.2 xx25=10` For HCl = `N_2V_2=10xx1` = 10 `THEREFORE` Mole of Acid = Moles of Base So pH = 7.0 |
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