1.

If 25 ml 0.2 M Ca(OH)_2 is neutralized by 10 ml, 1 M HCl than the pH of solution is …..

Answer»

1.37
9
12
7

Solution :for base `CA(OH)_2` MILLIMOLE =`M_1V_1`
`=2xxM_1xxV_1`
`=2xx0.2 xx25=10`
For HCl = `N_2V_2=10xx1` = 10
`THEREFORE` Mole of Acid = Moles of Base
So pH = 7.0


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