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If 2a + 3b - 5c = 0, then ratio in which c divides AB is |
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Answer» 3 : 2 INTERNALLY `implies (2a+3b)/(5)=c` `implies (2a+3b)/(2+3)=c` `implies (a+(3)/(2)b)/(1+(3)/(2))=c"...(i)"` Let c divides AB in the ratio `LAMBDA : 1`. Then, `c=(a+lambdab)/(1+lambda)"... (ii)"` On comparing Eqs. (i) and (ii), we get `lambda = (3)/(2)` So, required ratio is 3 : 2 internally.
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