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If 2a+3b+c=0, " then " axx b +b xx c+c xx a is equal to |
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Answer» `6(bxxc)` `RARR 2a+3b=-c` Taking cross product with a and b respectively, we GET `2(axxa)+3(AXXB)=axxc` `rArr 3(axxb)=cxxa` .....(ii) and `2(bxxa)+3(bxxb)=-bxxc` `rArr 2(axxb)=bxxc` ......(ii) Now , `axxb+bxxc+cxxa` `=axxb+bxxc+3(axxb)` `=4(axxb)+bxxc` `=2(bxxc)+bxxc` `=3(bxxc)` . |
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