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If `2f(x)-3f(1/x)=x^2(x!=0),`then `f(2)`is equal to(a)`-7/4("b")""5/2`(c) -1 (d) noneof these |
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Answer» `2f(x) - 3f(1/x) = x^2` When `x = 2`, `2f(2)-3f(1/2) = 4 ->(1)` When `x = 1/2`, `2f(1/2) - 3f(2) = 1/4->(2)` Nw, multiplying (1) with `2` and (2) with `3` and then adding (1) and (2), `4f(2)-6f(1/2)+6f(1/2)-9f(2) = 8+3/4` `=>-5f(2) = 35/4` `=>f(2) = -7/4` So, option `(a)` is the correct ooption. |
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