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If `2le||x-2|-1|le3`, then `x` belongs to intervalA. `[-2, -1]uu[5, 6]`B. `[-4, 6]`C. `(-oo, -4]uu[6, oo]`D. `[0, 1]uu[5,6]` |
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Answer» Correct Answer - A If `2 le ||x-2|-1|le3` ……….. `2le||x-2|-1|le3` (i) `|x-2|-1|ge2 or |x-2|-1le -2` `x ge 5 , or , x le -1` (ii) `le 3` `-3 le |x-2|-1le3` `-2le |x-2|le 4` `|x-2|le4` `-2le x le 6` `(i)nn(ii) implies x epsilon [-2, -1]uu[5,6]` |
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