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If (2n+1) θ=π, then 2n cos θ cos 2θ ⋯ cos 22 θ⋯ 2n−1θ= |
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Answer» If (2n+1) θ=π, then 2n cos θ cos 2θ ⋯ cos 22 θ⋯ 2n−1θ= |
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