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If `2sin 2 theta =sqrt(3) " then " theta=?`A. `30^(@)`B. `45^(@)`C. `60^(@)`D. `90^(@)` |
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Answer» Correct Answer - A `2sin2theta=sqrt(3)rArr sin2 theta=(sqrt(3))/(2)=sin60^(@)rArr 2 theta=60^(@)rArrtheta=30^(@).` |
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