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If 2sin2θ = √3, prove that θ = 30°. |
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Answer» Given that 2sin2θ = √3 ⇒ sin2θ = \(\frac{\sqrt3}2\) = sin60° (∵ sin60° = \(\frac{\sqrt3}2\) ) ⇒ 2θ = 60° (By comparing the angle) ⇒ θ = \(\frac{60°}2\) = 30° Hence Proved |
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