1.

If 2sin2θ = √3, prove that θ = 30°.

Answer»

Given that 2sin2θ = √3 

⇒ sin2θ = \(\frac{\sqrt3}2\) = sin60° (∵ sin60° = \(\frac{\sqrt3}2\) )

⇒ 2θ = 60° (By comparing the angle)

⇒ θ = \(\frac{60°}2\) = 30°

Hence Proved



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