If 2tan2α tan2β tan2γ+tan2αtan2β+tan2βtan2γ+tan2γtan2α=1 (whe – InterviewSolution

1.	If 2tan2α tan2β tan2γ+tan2αtan2β+tan2βtan2γ+tan2γtan2α=1 (where, α,β,γ≠(2n+1)π2,≠nπ,nϵI) then
Answer» If $2 t a n^{2} α t a n^{2} β t a n^{2} γ + t a n^{2} α t a n^{2} β + t a n^{2} β t a n^{2} γ + t a n^{2} γ t a n^{2} α = 1$ (where, $α, β, γ \neq (2 n + 1) \frac{π}{2}, \neq n π, n ϵ I$ ) then

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