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| 1. |
If 2x^3+3y^2+4z^2-√6xy-2√3yz-2√2xz=0,then find the value of (2x^2+3y^2+16z^2+2√6xy-8√3yz-8√2xz) |
| Answer» If 2x^3+3y^2+4z^2-√6xy-2√3yz-2√2xz=0,then find the value of (2x^2+3y^2+16z^2+2√6xy-8√3yz-8√2xz) | |