if (2x – 30)°, 2x° and (3x – 40)° are the angles in Arithmeti

1.	if (2x – 30)°, 2x° and (3x – 40)° are the angles in Arithmetic progression then find the largest angle?1. 170°2. 110°3. 130°4. 140°
Answer» Correct Answer - Option 1 : 170° Given: Three angles (2x – 30)°, 2x° and (3x - 40)° are given Formula Used: If a₁, a₂ and a₃ are the terms in arithmetic progression, then a₂ – a₁ = a₃ – a₂ Calculation: It is given in the question that the angles are in arithmetic progression, 2x – (2x – 30)° = (3x – 40)° - 2x ⇒ 2x – 2x + 30 = x – 40 ⇒ 30 = x – 40 ⇒ x = 70° Angles = 110°, 140° and 170° ∴ The largest angle is 170°

if (2x – 30)°, 2x° and (3x – 40)° are the angles in Arithmetic progression then find the largest angle?1. 170°2. 110°3. 130°4. 140°

Answer» Correct Answer - Option 1 : 170°

Given:

Three angles (2x – 30)°, 2x° and (3x - 40)° are given

Formula Used:

If a₁, a₂ and a₃ are the terms in arithmetic progression, then

a₂ – a₁ = a₃ – a₂

Calculation:

It is given in the question that the angles are in arithmetic progression,

2x – (2x – 30)° = (3x – 40)° - 2x

⇒ 2x – 2x + 30 = x – 40

⇒ 30 = x – 40

⇒ x = 70°

Angles = 110°, 140° and 170°

∴ The largest angle is 170°

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if (2x – 30)°, 2x° and (3x – 40)° are the angles in Arithmetic progression then find the largest angle?1. 170°2. 110°3. 130°4. 140°

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