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If ∫2x+5√7−6x−x2dx=A√7−6x−x2+Bsin−1(x+34)+C (where C is a constant of integration), then the orderd pair (A,B) is equal to : |
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Answer» If ∫2x+5√7−6x−x2dx=A√7−6x−x2+Bsin−1(x+34)+C (where C is a constant of integration), then the orderd pair (A,B) is equal to : |
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