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If 2x2 + (a - 10)x + 33/2 = 2a, a ∈ z+ has real roots, then minimum value of 'a' is equal to |
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Answer» D ≥ 0 (a - 10)2 - 4(2)(33/2 - 2a) ≥ 0 (a - 10)2 - 4(33 - 4a) ≥ 0 a2 - 4a - 32 ≥ 0 ⇒ a ∈ (- ∞, - 4] ∪ [8, ∞)
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