If ∫2x2sec2x dx(x sec2x−tan x)2=f(x)+cosx+x+c, where C is constant – InterviewSolution

1.	If ∫2x2sec2x dx(x sec2x−tan x)2=f(x)+cosx+x+c, where C is constant of integration, then value of f(π4)−f(−π4) is equal to
Answer» If $\int \frac{2 x^{2} s e c^{2} x d x}{(x s e c^{2} x - t a n x)^{2}} = f (x) + c o s x + x + c$ , where C is constant of integration, then value of $f (\frac{π}{4}) - f (- \frac{π}{4})$ is equal to

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