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| 1. |
If $3 A+4 B T=\left( \begin{array}{rrr}{7} & {-10} & {17} \\ {0} & {6} & {31}\end{array}\right)$ and $2 B-3 A^{T}=\left( \begin{array}{cc}{-1} & {18} \\ {4} & {-6} \\ {-5} & {-7}\end{array}\right)$ then $B=$1) $\left( \begin{array}{rr}{1} & {3} \\ {-1} & {0} \\ {-2} & {-4}\end{array}\right) \quad$ 2) $\left( \begin{array}{ll}{1} & {3} \\ {1} & {0} \\ {2} & {4}\end{array}\right)$3) $\left( \begin{array}{rr}{1-3} \\ {-1} & {0} \\ {2} & {4}\end{array}\right) \quad 4 ) \left( \begin{array}{rr}{-1} & {-3} \\ {1} & {0} \\ {2} & {4}\end{array}\right)$ |
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