Saved Bookmarks
| 1. |
If 3 + k, 18 – k, 5k + 1 are in A.P. then find k? |
|
Answer» 3 + k, 18 – k, 5k + 1 are in AP ∴ t2 – t1 = t3 – t2 (common difference is same) 18 – k – (3 + k) = 5k + 1 – (18 – k) 18 – k – 3 – k = 5k + 1 – 18 + k 15 – 2k = 6k – 17 32 = 8k k = 32/8 = 4 The value of k = 4 |
|