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If √3 sinθ - cosθ = 0 and 0˚< θ < 90˚, find the value of θ. |
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Answer» √3 sinθ = cosθ \(\frac{sin\theta}{cos\theta}\) = \(\frac{1}{\sqrt{3}}\) tanθ = \(\frac{1}{\sqrt{3}}\) θ = 30˚ |
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