If 3 tan θ = 4 then (3sin θ + 2cos θ)/(3sin θ – 2cosθ) = ?(A) 2

1.	If 3 tan θ = 4 then (3sin θ + 2cos θ)/(3sin θ – 2cosθ) = ?(A) 2(B) 3(C) 4(D) 5
Answer» The correct option is (B) 3. 3tan θ = 4 tan θ = 4/3 Given expression = (3sin θ + 2cos θ)/(3sin θ – 2cosθ) = (3tan θ + 2)/(3tan θ – 2) [dividing num. and denom. By cos θ] = (3 x 4/3 + 2)/(3 x 4/3 – 2) = (4 + 2)/(4 – 2) = 6/2 = 3

If 3 tan θ = 4 then (3sin θ + 2cos θ)/(3sin θ – 2cosθ) = ?(A) 2(B) 3(C) 4(D) 5

Answer»

The correct option is (B) 3.

3tan θ = 4

tan θ = 4/3

Given expression

= (3sin θ + 2cos θ)/(3sin θ – 2cosθ)

= (3tan θ + 2)/(3tan θ – 2) [dividing num. and denom. By cos θ]

= (3 x 4/3 + 2)/(3 x 4/3 – 2)

= (4 + 2)/(4 – 2)

= 6/2

= 3