If 30 mL of `H_(2)` and 20 mL of `O_(2)` reacts to form water, what is left at the end of the reaction?A. 10 mL of `H_(2)`B. 5 mL of `H_(2)`C. 10 mL of `O_(2)`D. 5 mL of `O_(2)`

If 30 mL of `H_(2)` and 20 mL of `O_(2)` reacts to form water, what is

1.	If 30 mL of `H_(2)` and 20 mL of `O_(2)` reacts to form water, what is left at the end of the reaction?A. 10 mL of `H_(2)`B. 5 mL of `H_(2)`C. 10 mL of `O_(2)`D. 5 mL of `O_(2)`
Answer» Correct Answer - D `underset(2vol)(2H_(2))+underset(1vol)(O_(2))to2H_(2)O` 2 mole of `H_(2)` reacts with 1 vol of `O_(2)` to give water. Therefore, 30 mL of `H_(2)` will reacts with 15 mL of `O_(2)` to give water. Here, `H_(2)` is the limiting reactant. Volume of `O_(2)` left unreacted = 20-15=5 mL

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If 30 mL of `H_(2)` and 20 mL of `O_(2)` reacts to form water, what is left at the end of the reaction?A. 10 mL of `H_(2)`B. 5 mL of `H_(2)`C. 10 mL of `O_(2)`D. 5 mL of `O_(2)`

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