If `3F` of electrictiy is passed through the solutions of `AgNO_3, CuSO_4` and `Auc=CL_3`, the molar ration of the cations deposited at the cathode is .A. `1:1:1`B. `1:2:3`C. `3:2:1`D. `6:3:2`

If `3F` of electrictiy is passed through the solutions of `AgNO_3, CuS

1.	If `3F` of electrictiy is passed through the solutions of `AgNO_3, CuSO_4` and `Auc=CL_3`, the molar ration of the cations deposited at the cathode is .A. `1:1:1`B. `1:2:3`C. `3:2:1`D. `6:3:2`
Answer» Correct Answer - D Since `Ag^+ + e^_ rarr Ag, Cu^(2+) + 2 e^(-) rarr Cu, Au^(3+) +3e^(-) rarr Au`, ` 3F` of electricity will depostit `3` moles of Ag, `1.5 ` moles of coppre, and `1` mole of gole. Therefpre, the molar ration is ` 3:1.5:1` or `6: 3:2`.

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If `3F` of electrictiy is passed through the solutions of `AgNO_3, CuSO_4` and `Auc=CL_3`, the molar ration of the cations deposited at the cathode is .A. `1:1:1`B. `1:2:3`C. `3:2:1`D. `6:3:2`

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