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If `(3k+4l+6m+7n)/(3k+4l-6m-7n) = (3k-4l+6m-7n)/(3k-4l-6m+7n)`,then show that k, 2m, 4l and 7n are in proportion. |
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Answer» `(3k+4l+6m+7n)/(3k+4l-6m-7n) = (3k-4l+6m-7n)/(3k-4l-6m+7n)` `rArr((3k+4l)+(6m+7n))/((3k+4l)-(6m+7n)) = ((3k-4l)+(6m-7n))/((3k-4l)-(6m+7n))` `rArr (3k+4l)/(6m+7n) = (3k-4l)/(6m-7n) rArr(3k+4l)/(3k-4l) = (6m+7n)/(6m-7n)` ` rArr (3k)/(4l) = (6m)/(7n) rArr k/(4l)=(2m)/(7n)` ` rArr k/(2m) = (4l)/(7n)` `:. ` k, 2m, 4l and 7n are in proprotion. |
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