1.

If 3π/4∫−π/4eπ/4dx(ex+eπ/4)(sinx+cosx)=kπ/2∫−π/2secxdx, then the value of k is

Answer»

If 3π/4π/4eπ/4dx(ex+eπ/4)(sinx+cosx)=kπ/2π/2secxdx, then the value of k is



Discussion

No Comment Found

Related InterviewSolutions