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If 3π/4∫−π/4eπ/4dx(ex+eπ/4)(sinx+cosx)=kπ/2∫−π/2secxdx, then the value of k is |
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Answer» If 3π/4∫−π/4eπ/4dx(ex+eπ/4)(sinx+cosx)=kπ/2∫−π/2secxdx, then the value of k is |
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