If (3x+12)(3x−12)=9x2 -p then the value of p is (a) 0 (b) −14 (c) 14 (d) 12

If (3x+12)(3x−12)=9x2 -p then the value of p is (a) 0 (b) −14 (c)

1.	If (3x+12)(3x−12)=9x2 -p then the value of p is (a) 0 (b) −14 (c) 14 (d) 12
Answer» If $(3 x + \frac{1}{2}) (3 x - \frac{1}{2}) = 9 x^{2}$ -p then the value of p is (a) 0 (b) $- \frac{1}{4}$ (c) $\frac{1}{4}$ (d) $\frac{1}{2}$