If 3x_2y=11 and xy=12 find the value of 27x3-8y3

1.	If 3x_2y=11 and xy=12 find the value of 27x3-8y3
Answer» We know that,(3x - 2y)3 = (3x)3 - (2y)3 - 3\xa0{tex}\\times{/tex}\xa03x\xa0{tex}\\times{/tex}\xa02y(3x - 2y){tex}\\Rightarrow{/tex}\xa0(11)3 = 27x3 - 8y3 - 18\xa0{tex}\\times{/tex}\xa012\xa0{tex}\\times{/tex}\xa011 [\xa0{tex}\\because{/tex}\xa03x - 2y = 11 and xy = 12]{tex}\\Rightarrow{/tex}\xa01331 = 27x3 - 8y3 - 2376{tex}\\Rightarrow{/tex}\xa027x3 - 8y3 = 2376 + 1331{tex}\\Rightarrow{/tex}\xa027x3 - 8y3 = 3707

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