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If 4 g of NaOH dissolves in 36 g of H_(2)O, calculate the mole fraction of each component in the solution. Also, determine the molarity of solution (specific gravity of solution is 1 g mL^(-1)). |
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Answer» SOLUTION :NUMBER of moles of NaOH, `n_(NaOH)= (4)/(40) = 0.1` mol `{n=("Mass(g)")/("Molar mass")}` Similarly, `n_(H_(2)O)=(36)/(18)=2` mol Mole fraction of solute `X_(NaOH) = ("moles of NaOH")/("moles of NaOH" + "moles of "H_(2)O)` `X_(NaOH)=(0.1)/(0.1+2)=0.0476` `X_(H_(2)O)=(n_(H_(2)O))/(n_(NaOH)+n_(H_(2)O))` `=(2)/(0.1+2)=0.9524` Total mass of solution `=("mass of solute")+("mass of solvent")` `=4+36=40g` Volume of solution `=("Mass of solution")/("SPECIFIC gravity")` `=(40g)/(1g mL^(-1))=40 mL` Molarity `=("Moles of solute " xx 1000)/("Volume of solution(mL)")` `=(0.1xx1000)/(40) = 2.5M` |
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