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If -4 is a root of the equationx2 + px – 4 = 0 and if the equationx2 + px + q = 0 has equal roots, find the values of p and q. |
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Answer» Let p(x) = x2 + px – 4 – 4 is the root of the equation P(-4) = 0 16 – 4p – 4 = 0 -4p + 12 = 0 -4p = -12 p = 12/4 = 3 The equation x2 + px + q = 0 has equal roots x2 + 3 x + q = 0 Here a = 1, b = 3, c = q Since the roots are real and equal b2 – 4 ac = 0 32 – 4(1)(q) = 0 9 – 4q = 0 9 = 4q q = 9/4 The value of p = 3 and q = 9/4 |
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