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If 4 litre of `H_(2)` gas at 400 mm Hg and `47^(@)C` is transferred to 19 litre flask at `107^(@)C`. Then pressure of `H_(2)` gas is:A. 191.7mm of HgB. 100 mm of HgC. 158.4 mm of HgD. 200 mm of Hg |
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Answer» `(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2))` `(400xx4)/(320)=(P_(2)xx19)/(180)rArrP_(2)=100mm` of Hg |
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