1.

If 4a2+9b2+16c2=2(3ab+6bc+4ca), where a,b,c are non-zero numbers, then a,b,c are in

Answer»

If 4a2+9b2+16c2=2(3ab+6bc+4ca), where a,b,c are non-zero numbers, then a,b,c are in



Discussion

No Comment Found