If 4c +20 ge 31, what is the least possible value of 12c +7 ?
Answer»
18 40 51 58
Solution :Subtract 20 from both sids of the INEQUALITY to find that `4c ge 11.` Multiply by `3:12c ge33.` FINALLY, add 7 to both SIDES:` 12 c + 7 ge 40.` So the least permissible VALUE for `12c +7` is 40 (B) is correct.