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If `4sin^(-1)x+6cos^(-1)x=3pi` then x= . . .A. `(1)/(sqrt(2))`B. `(1)/(2)`C. 0D. `(1)/(2)` |
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Answer» Correct Answer - C We have, `4 "sin"^(-1) x + 6 cos^(-1) x = 3 pi` `implies 4 "sin"^(-1) x + 6 ((pi)/(2) - "sin"^(-1) x) = 3 pi` `implies 4 "sin"^(-1) x + 3 pi - 6 "sin"^(-1) x = 3pi` `implies - 2 "sin"^(-1) x = 0 implies "sin"^(-1) x = 0` `implies x = "sin"(0) = 0` |
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