1.

If 5.0 g of Al react with 4.45 g of O_(2), empirical formula of aluminium oxide is

Answer»

`Al_(2)O_(3)`
`AlO_(2)`
`Al_(2)O`
`AlO_(3)`

Solution :Al : O
weight 5 : 4.45
MOLES = `(5)/(27):(4.45)/(16)`
= 80 : 120
= 2 : 3


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