If 5.6of KOH is present in (a) 500 mL and (b) 1 litre of solution, calculate the molarity of each of these solutions.

If 5.6of KOH is present in (a) 500 mL and (b) 1 litre of solution, cal

1.	If 5.6of KOH is present in (a) 500 mL and (b) 1 litre of solution, calculate the molarity of each of these solutions.
Answer» Solution :Mass of KOH `= 5.6 G` No. of moles `= (5.6)/(56) =0.1` mol (i) Volume of the solution `= 500 ml = 0.5 L` (ii) Volume of the solution = 1L Molarity `= ("Number of moles of SOLUTE")/("Volume of solution (in L)") = (0.1)/(0.5) = 0.2 M` (iii) Volume of the solution = 1L Molarity `= (0.1)/(1) = 0.1 M`