InterviewSolution
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InterviewSolution
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If 5 tan θ = 3, then what is the value of \((\frac{5 sin θ \,-\, 3 cos θ}{4 sin θ \,+\, 3 cos θ}) =\, ?\) |
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Answer» tan θ = \(\frac{3}{5}\) Now, \((\frac{5 sin θ \,-\, 3 cos θ}{4 sin θ \,+\, 3 cos θ})\) = \((\frac{5 sin θ \,-\, 3}{4 sin θ \,+\, 3})\) [Dividing numerator and denominator by cosθ] = \(\frac{3 - 3}{12 + 15}\over{5}\) = 0 |
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