If 50ml of 0.2M KOH is added to 40 mlof 0.5 M HCOOH. the pH of the resulting solutions is (Ka = 1.8 xx 10^(-4) log 18= 1.26)

If 50ml of 0.2M KOH is added to 40 mlof 0.5 M HCOOH. the pH of the res

1.	If 50ml of 0.2M KOH is added to 40 mlof 0.5 M HCOOH. the pH of the resulting solutions is (Ka = 1.8 xx 10^(-4) log 18= 1.26)
Answer» ` 3.74` ` 5.64` ` 7. 57 ` ` 3.42` Solution :In complete neutralisation ` THEREFORE" Acidic BUFFER pH " = pKa +log ""( S)/(A) ` ` = 4- log 1.8 + log"" ( 50 XX 0.2 )/(40 xx 0.5 -50 xx 0.2 ) ` ` =4-0.26 +log "" (10)/(20 - 10 )= 3.74`