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If `(5,12)a n d(24 ,7)`are the foci of a hyperbola passing through the origin, then`e=(sqrt(386))/(12)`(b) `e=(sqrt(386))/(13)``L R=(121)/6`(d) `L R=(121)/3`A. `e=sqrt(386)/12`B. `e=sqrt(386)/13`C. `LR=121//6`D. `LR=121//3` |
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Answer» Correct Answer - A::C We have foci `S_(1)(5, 12) and S_(2)(24, 7)`. Hyperbola passes through P(0, 0). `therefore" "|PS_(1)-PS_(2)|=2a` `2a=K` `"or "2a=|sqrt((24-0)^(2)+(7-0)^(2))-sqrt(12^(2)+5^(2))|=12` `therefore" "a=6` `S_(1)S_(2)=2ae=sqrt((24-5)^(2)+(12-7)^(2))=sqrt(386)` `therefore" "e=(sqrt(386))/(12)` `LR = (2b^(2))/(a)=(2a^(2)(e^(2)-1))/(a)` `=2xx6((386)/(144)-1)=(121)/(6)` |
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