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If 6.3 g of NaHC`O_(3)` are added to 15.0 g `CH_(3)`COOH solution, the residue is found of weight 18.0 g. What is the mass of `CO_(2)` released in the reaction? |
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Answer» The chemical reaction leading to products is `"sodium hydrogen carbonate"+"ethanoic acid" to underset("residue left")("sodium ethanoic solution")+underset("released")("carbon dioxide")` `"Mass of reactants"=(6.3+15.0)=21.3g` `"Mass of products"="Mass of residue"+"Mass of carbon dioxide released"` =18.0+x g According to law of conservation of mass. Mass of reactants=Mass of products 21.3g=(18.0+x)g or x=21.3-18.0=3.3g Mass of carbon dioxide released=3.3g |
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