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If 6.3 g of NaHCO_3 are added to 15.0 g of CH_3COOH solution, the residue is found to weigh 18.0 g. What is the mass of CO_2 released in the reaction ? |
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Answer» Solution :According to the law of conservation of mass, the total amount of reactants is always equal to the total amount of PRODUCTS in a chemical reaction. In the given CASE, Total amount of reactants `(NaHCO_(3))+CH_(3)COOH)` `=6.3 + 15.0 = 21.3 g` Suppose, x g of `CO_(2)` is released in the reaction, `therefore` Total amount of products (RESIDUE `+CO_(2)`) `=18.0 + xg` `therefore x= 3.3 g` Hence, the amount of C02 released in the reaction is 3.3 g. |
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