If 64y8 is exactly divisible by 3, then the least value of y isa. 0b. – InterviewSolution

1.

If 64y8 is exactly divisible by 3, then the least value of y isa. 0b. 1c. 2d. 3

Answer»

We know that the sum of the digits of a number is divisible by 3 then the whole number is divisible by 3

6+4+y+8 = multiple of 3

18+y= 0, 3, 6, 9….

18+y= 18

∴ y=18-18 = 0

The least value of y is 0

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