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If |(6i,-3i,1),(4,3i,-1),(20,3,i)| = x + iy then,(A) x = 3, y = 1(B) x = 1, y = 3(C) x = 0, y = 3(D) x = 0, y = 0 |
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Answer» Answer is (D) x = 0, y = 0 |
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