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If 78 is divided into three parts which are in the ratio \(1:\frac{1}{3}:\frac{1}{6}\), the middle part is 1). \(9\frac{1}{3}\)2). 133). \(17\frac{1}{3}\)4). \(18\frac{1}{3}\) |
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Answer» GIVEN, three parts are in the ratio $(1:\frac{1}{3}:\frac{1}{6})$ Let the first PART be a. Middle part = a/3 Last part = a/6 Given, 78 is DIVIDED into these three parts ∴ a + a/3 + a/6 = 78 ⇒ 9a/6 = 78 ⇒ a = 156/3 = 52 Now, Middle part = a/3 ⇒ Middle part = 52/3 = $(17\frac{1}{3})$ |
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