1.

If 78 is divided into three parts which are in the ratio \(1:\frac{1}{3}:\frac{1}{6}\), the middle part is 1). \(9\frac{1}{3}\)2). 133). \(17\frac{1}{3}\)4). \(18\frac{1}{3}\)

Answer»

GIVEN, three parts are in the ratio $(1:\frac{1}{3}:\frac{1}{6})$

Let the first PART be a.

Middle part = a/3

Last part = a/6

Given, 78 is DIVIDED into these three parts

∴ a + a/3 + a/6 = 78

⇒ 9a/6 = 78

⇒ a = 156/3 = 52

Now, Middle part = a/3

⇒ Middle part = 52/3 = $(17\frac{1}{3})$


Discussion

No Comment Found