1.

If 8 dipoles of charges of magnitude ± e are placed inside the cube. The electric flux coming out of cube will be(a) 16e/E0(b) 8e/E0(c) e/E0(d) zero

Answer»

Answer is : (d) zero

From Gauss theorem,

\(\phi_E=\frac{q_{in}}{E_0}\) \(=\frac{+8e-8e}{E_0}=0\)



Discussion

No Comment Found

Related InterviewSolutions