If 9n×32×(3n2)−(27)n33m×23=127 then m =

1.	If 9n×32×(3n2)−(27)n33m×23=127 then m =
Answer» If $\frac{9^{n} \times 3^{2} \times (3 \frac{n}{2}) - (27)^{n}}{3^{3 m} \times 2^{3}} = \frac{1}{27}$ then m =

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