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If 9th term of an a.p. is zero then proof that 29th term is double the 19th term

Answer» Too.long process.. you have done<br>Let a and b respectively be the first term and common difference of the AP Given A9=0So ,a+(9-1)d=0a+8d=0a=-8dNow ,29 th term= a+28d=-8d+28d=20d=2*10d=2(-8d+18d)=2(a+18d)=2*19th term Thus ,the 29 th term of the AP is double the 19th term


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