If 9x ^2+25y^2=181 and xy=-6 please find the value of 3x+5y.

1.	If 9x ^2+25y^2=181 and xy=-6 please find the value of 3x+5y.
Answer» (3x+5y)² =9x²+25y² +30xy(3x+5y)²=181 + 30*-6(3x+5y)²=181-180(3x+5y)²=13x+5y=1 xy product can be 6 iff there are (1,6), (2,3),(3,2) or (6,1) as x and y soo by putting values of x,y in the equation we got (3,2 ) as solutionBut the condition is xy=-6So x could be negative or y could be negativeHence there are two solutions of the eqn. 3x+5y , it could be (-3,2) or (3,-2) thats why we get different results as well for first solution we get 1 as the answer and -1 for the latter one. Therefore the equation would have positive or negative unity. Please give me my ans

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