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If A(0, 0) and C(6, -8) are end points of diagonal of a square then sum of square of abscissa of other vertex is

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Solution :Using concept of rotation
`(x+I y) - (3-4i) = [6-8i-(3-4i)]e^((i PI)/(2))`
`x = I y = (3-4i) + (3-4i)i`
`rArr x + i y = (3-4i)(1+i)`
`x + i y = 3- 4i + 3I + 4`
`= 7 - i`
x = 7, y = -1 similarly, x = -1, y = -7
`7^(2) + 1^(2) = 50`


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