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If A=⎡⎢⎣0121233a1⎤⎥⎦ and A−1=⎡⎢⎣1/2−1/21/2−43c5/2−3/21/2⎤⎥⎦, then a+c=

Answer» If A=0121233a1 and A1=1/21/21/243c5/23/21/2, then a+c=


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